Question

ABD is an isosceles triangle. AB = AD. Find ACB.​

Answer 1

∠ ACB = 39°

Explanation:

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ BDA is an exterior angle of Δ ACD , then

∠ CAD + ∠ ACB = ∠ ACD , that is

29° + ∠ ACB = 68° ( subtract 29° from both sides )

∠ ACB = 39°