Question

A waitress sold 11 ribeye steak dinners and 12 grilled salmon dinners, totaling $568.75 on a particular day. Another day she sold 14 ribeye steak dinners and 6 grilled salmon dinners, totaling $583.04 . How much did each type of dinner cost?

Answer 1

Steak dinners is 35.14

Salmon dinners is 15.18

Explanation:

Steak dinners is x

Salmon dinners is y

So

11x + 12y = 568.75

14x + 6y = 583.04

11x + 12y = 568.75

=> y = (568.75 - 11x)/12

Substitute

14x + 6[(568.75 - 11x)/12) = 583.04

14x + (568.75 - 11x)/2 = 1166.08

28x + 568.75 - 11 x = 1166.08

28x - 11x = 1166.08 - 568.75

17x = 597.33

x = 35.137 = 35.14

Substitute

y = (568.75 - 11x)/12

y = (568.75 - 386.54)/12

y = 182.21/12 = 15.18

Hope this helps.