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Find the equation of a line parallel to y = 12 that contains the point (3, 2).

User Sviklim
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1 Answer

6 votes

Answer:

y = 2

Explanation:

Let's first write the equation of y = 12 in slope-intercept form. Slope-intercept form is represented as:

y = mx + b

Where...

m: slope

b: y-intercept (the y-value at where the line intercepts the y-axis)

(x, y): any coordinate on the line

This line has a slope of 0 and a y-intercept of 12, therefore its equation is:

y = 0x + 12.

Parallel lines have the same slope. Therefore the equation of the parallel line can be represented as:

y = 0x + b

We need to find b, or the y-intercept.

Let's substitute the point given to us into the equation.

Solve for the y-intercept

y = 0x + b

2 = 0(3) + b

2 = 0 + b

b = 2

Therefore the equation of a line parallel to y = 12 that contains the point (3, 2) is y = 2.

User Cschwan
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