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Two containers designed to hold water are side by side, both in the shape of a

cylinder. Container A has a diameter of 18 feet and a height of 17 feet. Container B
has a diameter of 20 feet and a height of 16 feet. Container A is full of water and the
water is pumped into Container B until Container A is empty.
After the pumping is complete, what is the volume of water in Container B, to the
nearest tenth of a cubic foot?

User Below
by
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1 Answer

3 votes

Answer:

Volume of Cylinder A is pi times the area of the base times the height

π r2 h = (3.1416)(4)(4)(15) = 753.98 ft3

Volume of Cylinder B is likewise pi times the area of the base times the height

π r2 h = (3.1416)(6)(6)(7) = 791.68 ft3

After pumping all of Cyl A into Cyl B

there will remain empty space in B 791.68 – 753.98 = 37.7 ft3

The percentage this empty space is

of the entire volume is 37.7 / 791.68 = 0.0476 which is 4.8% when rounded to the nearest tenth

.

User Mark Van Proctor
by
8.9k points

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