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Given that f(x) = x²+3 find x when f(x)=54 ​

User Iwiznia
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Explanation:

In the place of f(x) plug in 54 and then simplify the eqaution.

[tex]54 = {x}^{2} + 3\\ {x}^{2} + 3 = 54 \\ {x}^{2} + 3 - 54 = 0 \\ \\ {x}^{2} -51 =0

{x}^{2}=51

x=(+-) the square root of 51

User IConnor
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