52.6k views
3 votes
He square

en
and
Find the x-intercepts of the parabola with
vertex (1,-13) and y-intercept (0,-11).
Write your answer in this form: (X₁,Y1), (X2,2).
If necessary, round to the nearest hundredth.
OPHO
Clear all
Enter the correct answer.
+?
DONE

1 Answer

0 votes

Answer:

-1.55, 3.55 to nearest hundredth.

Explanation:

First write this in vertex form:

f(x) = a(x - b)^2 + c

f(x) = a(x - 1)^2 - 13 where a is some constant.

f(x) = -11 when x = 0 so we have:

-11 = a(0 - 1)^2 - 13

a = -11 + 13 = 2.

intercept form is

f(x) = 2(x - 1)^2 - 13

When f(x) = 0 we have thd x-intercepts:

2(x - 1)^2 - 13 = 0

(x - 1)^2 = 6.5

x = ±√6.5 + 1

= 2.550 + 1, -2.550 + 1

x intercepts = 3.55, -1.55.

User Dhaivat Pandya
by
6.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.