163,635 views
16 votes
16 votes
Blues varied directly as greens and inversely as whites squared. If there were 3 greens when there were 4 blues and 2 whites, how many greens were required for 2 blues and 4 whites?​

User Patriotic
by
3.2k points

2 Answers

26 votes
26 votes

Step-by-step explanation:

there will be 3 greens

that is the answer

User Gamal A
by
2.7k points
18 votes
18 votes

Final Answer:

5 greens are required for 2 blues and 4 whites.

Step-by-step explanation:

Direct Proportion: Blues vary directly with greens (meaning they increase or decrease proportionally).

Inverse Proportion: Blues vary inversely with whites squared (meaning as whites squared increase, blues decrease proportionally).

Set Up Proportion: We can express the relationship as a proportion: B ∝ G / W^2.

Substitute Known Values: We know that when there are 3 greens (G) and 2 whites (W), there are 4 blues (B): 4 ∝ 3 / 2^2.

Solve for Constant of Proportionality: To find the constant of proportionality (k), we can multiply both sides by 4 * 2^2: 4 * 4 = k * 3. Solving for k, we get k = 16/3.

Apply Constant to New Scenario: For 2 blues and 4 whites, we can set up a new proportion: 2 ∝ G / 4^2.

Substitute Constant and Solve for Greens: Replace k with 16/3: 2 ∝ G / 16. Solving for G, we get G = 2 * 16 = 32.

Round to Nearest Whole Number: Since the number of greens should be a whole number, we round 32 up to the nearest whole number: G = 5.

Therefore, 5 greens are required for 2 blues and 4 whites.

User Manuvo
by
3.1k points