Question

Suppose z varies jointly with x and y. When x = 3, y = 8, z = 6. Find z, when x = 6 and y = 4.​

Answer 1

Explanation:

Z=x/y

z=Kx/y

where K is the constant

We substitute

6=6K/4

6=3k/2

we crossed multiply

6*2=3k

12=3k

we divide both sides by 3

12/3=3k/3

2=K

therefore: K=2

z=kx/y

z= 2(6)/4

z= 12/4

z= 3

Answer 2

Explanation:

z-kxy where=1/4

z=(xy/4)

z=6

that is the answer.