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Solve the inequality 8 + 3x < 2 + x and 2x + 23 ≤ 11

User Dave Sag
by
6.1k points

2 Answers

2 votes

1) 8 + 3x < 2

To solve this, you first want to subtract 8 from both sides to isolate 3x on one side.

This gives you 3x < 2 - 8, which can be simplified to 3x < -6.

After you have this, you want to get x on its own. To do this, divide both sides of the inequality by 3 to get x < -6

2) 2x + 23
\leq 11

For this one, we use the same steps. First, subtract 23 from both sides to isolate 2x, giving us 2x
\leq 11 - 23, which we simplify down to 2x
\leq -12.

From here, we divide both sides of the inequality by 2 to get x on its own. This gives us x
\leq -6

User Moog
by
4.9k points
3 votes

Answer:

8 + 3x < 2 + x the answer would be x<-3

2x + 23 ≤ 11 the answer would be
x\leq -6

User Neil T
by
5.3k points
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