Question

A tuna jumps out of the water with an initial velocity of 44 feet per second (assume its starting height is 0 feet). Use the vertical motion model, h 16t²+uts where is the initial velocity in feet per second and is is the height in feet, to calculate the amount of time the tuna is in the air before it hits the ground again. Round your answer to the nearest tenth if necessary. ​

Answer 1

The tuna is in the air for approximately 2.8 seconds before it hits the ground again.

Step-by-step explanation:

The vertical motion of the tuna can be described by the equation h = 16t² + ut, where h is the height in feet, t is the time in seconds, and u is the initial velocity in feet per second. In this case, the initial velocity u is 44 ft/s. We want to find the time it takes for the tuna to hit the ground again, so we set h = 0 and solve for t:

0 = 16t² + 44t

By factoring, we get:

t(16t + 44) = 0

So t = 0 or t = -44/16. Since time cannot be negative, the tuna is in the air for approximately 2.8 seconds before it hits the ground again.