Answer:
1. m ∠ 1 = 86°
m ∠ 2 = 4°
- Problem in the picture
2. m ∠ 1 = 6°
m ∠ 2 = 84°
Explanation:
I'm confused, so I'll just solve both problems (assuming that they are the same type of angle)
1.
m Z1 = (x+84)° and m2 = 2xº.
m ∠ 1 = (x + 84)°
m ∠ 2 = 2x°
Complementary angles are equal to 90°
(x + 84) + 2x = 90
x + 84 + 2x = 90
3x + 84 = 90
-84 -84
----------------------
3x = 6
÷3 ÷3
-----------
x = 2°
m ∠ 1 = (x + 84)°
m ∠ 1 = (2 + 84)°
m ∠ 1 = 86°
m ∠ 2 = 2x°
m ∠ 2 = 2(2)°
m ∠ 2 = 4°
2. (Problem in the picture)
m ∠ 1 = (x - 6)°
m ∠ 2 = 7x°
Complementary angles are equal to 90°
(x - 6) + 7x = 90
x - 6 + 7x = 90
8x - 6 = 90
+6 +6
---------------------
8x = 96
÷8 ÷8
----------------
x = 12
m ∠ 1 = (x - 6)°
m ∠ 1 = (12 - 6)°
m ∠ 1 = 6°
m ∠ 2 = 7x°
m ∠ 2 = 7(12)°
m ∠ 2 = 84°
I hope this helps!