Question

What is the distance in units between the points (6, -3) and (6, 1)?

Answer 1

Hope it helps because I solved it

Answer 2

`\large\boxed{\sf{4}}`

Explanation:

Given:

• Use the distance formula.

Distance formula:

`\rightarrow: \sf{√((x_2-x_1)^2+(y_2-y_1)^2) }}`

Solutions:

`\sf{√(\left(6-6\right)^2+\left(1-\left(-3\right)\right)^2)}}`

Solve.

PEMDAS stands for:

• Parentheses
• Exponents
• Multiply
• Divide
• Add
• Subtract

`\sf{1-\left(-3\right)=1+3}`

`\sf{\left(6-6\right)^2+\left(1+3\right)^2}`

Do parentheses first.

6-6=0

0²=0

0+(1+3)²

1+3=4

Then exponents.

4²=4*4=16

√16

Factor.

4²=16

√4²

√4²=4

Therefore, the distance in units between the points (6,-3) and (6,1) is 4, which is our answer.

I hope this helps, let me know if you have any questions.