Answer:
Choice A:
![2x^4+12x^3+26x^2+8x+12](https://img.qammunity.org/2023/formulas/mathematics/high-school/sqcp4cvou1cor7upaqdgavi8hpc37bqdnl.png)
Explanation:
This can be done without computing the entire product and difference with a little bit of thought. If you look at the answer choices they have different values for the coefficient of
Choices B and C do not even have a term for
![x^4](https://img.qammunity.org/2023/formulas/mathematics/high-school/43tdgdt8pc06fu77wwl3phtyryr869ykw8.png)
So if we focus on only the part of the multiplication which will produce an
term we can find the right choice
The area of Shape A is (3x² + 2)(7x² + 4x + 8)
One of the terms arises from 3x² x 7x² =
![21x^4](https://img.qammunity.org/2023/formulas/mathematics/high-school/ixtj75tfcs5p2qlslsxdjlsehms87nnuq9.png)
The area of Shape B = (3x²+2)(3x^2+2)
So the
Look at the answer choices.
The first component has x term
which is obtained by multiplying
(3x²)(3x²) =
![9x^4](https://img.qammunity.org/2023/formulas/mathematics/high-school/9aagzkru5fwcaiuhrj8tv28rlehekqsaph.png)
If we subtract the area of Shape B from Shape A , we get the
term as
![21x^4 - 9x^4 = 12x^4](https://img.qammunity.org/2023/formulas/mathematics/high-school/cbudm8z0nt4svqvkzjii71t14x9ij8v4rx.png)
The only choice which has
as a term is the first one, Choice A
So answer is Choice A:
![2x^4+12x^3+26x^2+8x+12](https://img.qammunity.org/2023/formulas/mathematics/high-school/sqcp4cvou1cor7upaqdgavi8hpc37bqdnl.png)