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In a tug-of-war match, one individual is pulling with a force of 10 N to the left while the other is pulling with 9 N to the left. What is the net force exerted on the rope? NEED THIS ANSWER ASAP

~1n to the left

~1n to the right

~19n to the right

~19n to the left

User Hardik Bar
by
5.8k points

1 Answer

1 vote

Answer:

F

x

=

T

F

x

=

m

a

x

=

0

As stated in the question, it would mean that

T

=

F

x

(so

T

F

x

=

0

). Thus, if

F

x

=

10 N

,

T

=

10 N

.

(Additionally, even if

m

is small,

a

x

must therefore be

0 m/s

2

.)

Step-by-step explanation:

While many people would like to simply add the forces from each end to get a total force, this is fundamentally incorrect.

This is an application of Newton's Third Law: "For every action there is an equal and opposite reaction." The only way someone on one end of the string can exert a force of 10 N on the other end of the string is of the other end of the string exerts a 10 N force in the opposite direction.

Suppose I hang a 1 kg mass from a spring scale. This pulls with a force of approximately 10 N. Next, remove the weight and attach the spring scale to a wall. Pull on the scale until it reads 1 kg. That's the same 10 N force that the weight (and gravity) exerted downward when it was hanging. Lastly, consider what would happen if you attached a second spring scale to the wall and the end of the string to that spring scale. When you pull one hard enough to make it read 1 kg, the spring scale on the opposite end will also show 1 kg. They are indicating equal forces in opposite directions.

User Gorjan
by
4.8k points