Question

Sodium metal is reacted with chlorine gas to produce 5.85g of a salt.

a. Find the mass of the reacted metal
b. Fid the volume of the reacted gas at STP.
(Na=23, C1=35.5, at STP: 1mole of gas has 22.4L

Answer 1

A= 2.3g

B= 1.2L

Step-by-step explanation:

a) Find the mass of the reacted metal

2Na + Cl2 → 2NaCl

46 71 117

X 5.85

From the chemical equation

117/5.85 = 46/x

X= (46x5.85)/117

= 2.3g

So, the mass of the reacted metal is 2.3g

b) Find the volume of the reacted gas at STP

at STP: 71g of CL2 has 22.4l

Y of Cl2 has V

V= (Y x 22.4L) / 71 where y=?

From the chemical equation

117 / 5.85 = 71 / Y

Y= (71x5.85) / 117

= 3.55

V= (3.55x22.4) / 71

= 1.12L

So, the volume of the reacted gas at STP is 1.12L

Answer 2

35.5 this is the answer ok