22.0k views
0 votes
Is there a mistake in the FT identity of integration, if yes what is the right one​

User Ants
by
8.1k points

1 Answer

4 votes

Answer:

The right one is;


{ \rm{ (1)/( \omega) x(t) \to \int X( \omega)}}

X(w) is the fourier transform and the FT pair identity is as below;


{ \tt{x(t) =X( \omega) {e}^{ - (k \omega _(0)t )} \: dt }} \\ { \tt{x(t) = \int X( \omega) { e}^{ - (k\omega _(0)t)} d t}} \\ { \tt{x(t) = k\omega _(0) \{x( \omega) {e}^{ -k(\omega _(0)t) } }}

Assume k is 1


{ \tt{ (x(t))/(\omega _(0)) = \int x( \omega _(0)) }}

User Justin Lessard
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories