Question

What is an equation of the line that passes through the points
(-8, 2) and
(-4, -3)?

Answer 1

`y = -(5)/(4)x - 8`

Explanation:

to solve this equation we must first find the slope using (y2 - y1) / (x2 - x1)

plug the points in

(-3 - 2) / (-4 - -8)

now subtract

(-5) / 4

that is your slope

-5/4

now put it in y = mx + b form

`y = -(5)/(4)x + b`

now plug in the find b

`2 = -(5)/(4)(-8) + b`

`2 = 10 + b`

b = -8

now add that to your equation

`y = -(5)/(4)x - 8`

that is your equation

Answer 2

y = -5/4x -8

Explanation:

Step 1: plot the points.

Step 2: Calculate the rise/run for the points

-5/4

Step 3: draw a line between them

Step 4: find the y-int

-8

y=mx+b where x and y are variables, m is the slope and b is the y-int

y = -5/4x -8

Hope that helps