Question

Wite an equation perpendicular to y=-2x-7 that passes through the point (4,3)

Answer 1

y = 1/2 x + 1.

Explanation:

A line perpendicular to a line with slope m will have a slope of -1/m.

The line y = -2x - 7 will have a slope of -1/ -2 = 1/2.

Using the point-slope form of a straight line

y - y1 = m(x - x1)

Here m = 1/2 and (x1, y1) = (4, 3).

So, y - 3 = 1/2(x - 4)

y = 1/2x - 2 + 3

y = 1/2 x + 1.