Answer:
x = -1, y = 1
Explanation:
Solve the following system:
{y = 3 x + 4 | (equation 1)
y = x + 2 | (equation 2)
Express the system in standard form:
{-(3 x) + y = 4 | (equation 1)
-x + y = 2 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{-(3 x) + y = 4 | (equation 1)
0 x + (2 y)/3 = 2/3 | (equation 2)
Multiply equation 2 by 3/2:
{-(3 x) + y = 4 | (equation 1)
0 x + y = 1 | (equation 2)
Subtract equation 2 from equation 1:
{-(3 x) + 0 y = 3 | (equation 1)
0 x + y = 1 | (equation 2)
Divide equation 1 by -3:
{x + 0 y = -1 | (equation 1)
0 x + y = 1 | (equation 2)
Collect results:
Answer: {x = -1, y = 1