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The specific heat of the metallic element rhodium is 0. 240 j/g-k at 25°c. If 586 j of heat is added to an 80. 0 g block of rhodium metal that is initially at 25. 0°c, what is the expected final temperature of the block?.

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Answer:

55.5 ° C

Step-by-step explanation:

A unit of K and a degre C are the same increment

586 j / (80 g C ) = .240

C = 30.5 degree increase from 25 c = 55.5 ° C

User Charles Gomes
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