Answer:
Force carried by each rod, F = 3800 / 2 = 1900 lb
Cross-sectional area of each rod, A = pi ( d^2) / 4
A = pi * 0.375 * 0.375 / 4 = 0.1104 in^2
Stress in each rod = F / A = 1900 / 0.1104
= 17.21 * 1000 psi
= 17.21 ksi
Step-by-step explanation:
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