Answer:
Question 1:
• In A, the main carbon has four bonds [two double bonds ] i.e; (=C=) hence it cannot allow any incoming electron. This makes it thermodynamically stable because it's reactivity carbon is fully bonded.
In B, the main carbon has only three bonds i.e;
(=C–) hence it will allow only one pair of incoming electrons hence reaction taking place.
Question 2:
Note: Any halo-alkane or alkyl-halide such as methyl iodide, methyl chloride, ethyl bromide are reagents used to add alkyl groups to amide molecules.
• So, Methyl Iodide will not react with C because C lacks an amide or nitrile group. To add an alkyl group to C, we shall use potassium hydroxide and any alcohol in presence of dry ether at room temperature.
• Methyl Iodide will react with D because D has an amide group which is electron efficient hence reaction will take place so easily.
Question 3
Note: Nucleophiles are electron donating molecules.
Electrophiles are electron recipients.
• F will react with nucleophiles because F has a carbonyl group i.e; (–HC=O ) which is an electron recipient. But this occurs after the oxygen atom reacting with an hydroxide to form an oxide.
E will not react, because the main carbon has a double bond which are nucleophiles.
