Question

Find the equation of the quadratic function given the vertex and a point on the parabola.

v= (3,0), p=(1,4) ​

Answer 1

y = x² - 6x + 9

Explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (3, 0 ) , then

y = a(x - 3)² + 0

To find a substitute (1, 4) into the equation

4 = a(1 - 3)² = a(- 2)² = 4a ( divide both sides by 4 )

1 = a

y = (x - 3)² = x² - 6x + 9