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What is the perimeter, in feet, of a rectangle whose length is four times its width which is 8 feet?
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Jan 3, 2023
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What is the perimeter, in feet, of a rectangle whose length is four times its width
which is 8 feet?
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Ergin
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Ergin
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Answer is 80 feet
Step by step
We know perimeter is
P = 2L + 2W
We know L = 4W
We know W = 8
Substitute these into our formula and solve
P = 2(4 x 8) + 2(8)
P = 2(32) + 16
P = 64 + 16
P = 80 ft
Problem solved!
Tom Feiner
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Jan 8, 2023
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Tom Feiner
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