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What is the equation of the line that passes through the point (-3,7)(−3,7) and has a slope of -5/3

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Explanation:

what form should the equation have ?

I assume slope-intercept

y = ax + b

"a" being the slope, "b" being the y-intercept (the y value when x = 0).

but since we have the slope and a point, we can start with the point-slope form and transform it :

y - y1 = a(x - x1)

"a" is again the slope, (x1, y1) is the point.

so,

y - 7 = -5/3 × (x - -3) = -5/3 × (x + 3) = -5x/3 - 5

and therefore

y = -5x/3 + 2

User Mike Hay
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