How do I write 7^2x-3 in a(b^x) form

asked Dec 7, 2023 209k views

1 vote

How do I write 7^2x-3
in a(b^x) form

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4 votes

Answer:
$(1)/(343)\left(49^x\right)$

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Work Shown:

$7^(2x-3) = 7^(2x)*7^(-3)\\\\7^(2x-3) = 7^(-3)*7^(2x)\\\\7^(2x-3) = (1)/(7^3)*\left(7^(2)\right)^(x)\\\\7^(2x-3) = (1)/(343)*\left(49^x\right)\\\\$

The answer is in the form a(b^x) where,

a = 1/343

b = 49

Josha Inglis answered Dec 11, 2023

6.1k points

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