Question

REALLY URGENT!!!

Question: Find the equation of the line specified.

Perpendicular to 3x + y = -7 and passing through (1,8)

(i really need an explanation on how to do this)

Answer 1

`y=(1)/(3)x+7.6666`

Explanation:

First we must convert
`3x+y=-7` into slope-intercept form!

To do this we simply just need to subtract -3x from the 3x on the left and move it to the right side. This would result in:
`y = -3x-7`

Now that we have our slope-intercept form for the equation remember that to find the equation that is perpendicular to the given equation, you need to use the opposite reciprocal of the slope. This would be
`(1)/(3)` as that is the reciprocal and opposite of
`-(3)/(1)`

Now in order to find the "b" variable of the equation that goes through the ordered pair (1, 8) we need to plug it in to the given equation!

That equation would be:
`y=(1)/(3)x-7`

Given that x = 1 and y = 8 we can plug those in like so:

`8=(1)/(3)(1)+b`

(make sure to set the -7 to b as that's what we're solving for)

1 / 3 is 0.3333 (infinitely repeating)

Next we need to subtract 0.3333 from 8, which would be 7.6666 (infinitely repeating) Remember that the variable needs to be "alone"!

Now we have our "b" for the equation! Hence the equation would be:

`y=(1)/(3)x+7.6666`

(you can also use
`(23)/(3)` for the b as that is the "exact form" of 1 / 3 but they both work)

Hope this helps! Feel free to ask questions!