409,795 views
32 votes
32 votes
(−4 + 5) − (6 + 7) = x x 0

User Vishwajeet
by
3.0k points

1 Answer

12 votes
12 votes

1

Add the numbers

(

4

+

5

)

(

6

+

7

)

=

0

({\color{#c92786}{-4}}+{\color{#c92786}{5}})-(6+7)=xx^{0}

(−4+5)−(6+7)=xx0

(

1

)

(

6

+

7

)

=

0

({\color{#c92786}{1}})-(6+7)=xx^{0}

(1)−(6+7)=xx0

2

Add the numbers

1

(

6

+

7

)

=

0

1-({\color{#c92786}{6}}+{\color{#c92786}{7}})=xx^{0}

1−(6+7)=xx0

1

(

1

3

)

=

0

1-({\color{#c92786}{13}})=xx^{0}

1−(13)=xx0

3

Multiply the numbers

1

1

1

3

=

0

1{\color{#c92786}{-1}} \cdot {\color{#c92786}{13}}=xx^{0}

1−1⋅13=xx0

1

1

3

=

0

1{\color{#c92786}{-13}}=xx^{0}

1−13=xx0

4

Subtract the numbers

1

1

3

=

0

{\color{#c92786}{1-13}}=xx^{0}

1−13=xx0

1

2

=

0

{\color{#c92786}{-12}}=xx^{0}

−12=xx0

5

Combine exponents

1

2

=

0

-12={\color{#c92786}{xx^{0}}}

−12=xx0

1

2

=

1

-12={\color{#c92786}{x^{1}}}

−12=x1

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Solution

1

2

=

1

User Amin Ba
by
2.6k points
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