Question

Find the derivative:
y=(1+cosx)/(1+sinx)

I NEED STEPS

Answer 1

`y=\cfrac{1+cos(x)}{1+sin(x)}\implies \cfrac{dy}{dx}=\stackrel{\textit{\Large quotient rule }}{\cfrac{-sin(x)( ~~ 1+sin(x)~~ )-( ~~ 1+cos(x) ~~ )cos(x)}{( ~~ 1+sin(x) ~~ )^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{-sin(x)-sin^2(x)-cos(x)-cos^2(x)}{( ~~ 1+sin(x) ~~ )^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{-sin(x)-cos(x)-( ~~ sin^2(x)+cos^2(x) ~~ )}{( ~~ 1+sin(x) ~~ )^2} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill {\LARGE \begin{array}{llll} \cfrac{dy}{dx}=\cfrac{-sin(x)-cos(x)-1}{( ~~ 1+sin(x) ~~ )^2} \end{array}}~\hfill`