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Can somebody help and not give a link?

Can somebody help and not give a link?-example-1
User SKINDER
by
3.1k points

2 Answers

24 votes
24 votes

Answer:

m<PQR = 150°

Explanation:

<PQR = (12x-6)°

<SQR = (9x+17)°

<PQS = 16°

find m<PQR.

since <SQR + <PQS = <PQR,

then (9x+17)° + 16° = (12x-6)°

combine like terms;

9x + 17 + 16

9x + 33 = 12x - 6

subtract 33 from both sides;

9x = 12x - 39

subtract 12x from both sides;

-3x = -39

divide by -3;

x = 13, then input x into the equation for m<PQR;

m<PQR = (12x-6)°,

(12(13)x - 6)°

(156 - 6)°

Answer: 150°

User Unused
by
2.4k points
27 votes
27 votes

Answer:

∠ PQR = 150°

Explanation:

∠ PQR = ∠ PQS + ∠ SQR , substitute values

12x - 6 = 16 + 9x + 17

12x - 6 = 9x + 33 ( subtract 9x from both sides )

3x - 6 = 33 ( add 6 to both sides )

3x = 39 ( divide both sides by 3 )

x = 13

Then

∠ PQR = 12x - 6 = 12(13) - 6 = 156 - 6 = 150°

User Kamaraju
by
3.0k points