Answer:
The answer is No Solution.
Explanation:
We can't add the two systems, so let's look for x. We would need to multiple them by (-6) and 2, which are the numbers in front of x. One must be a negative.
(2x + 3y = 7) * (-6)
(6x + 9y = 6) * 2
_____________
(-12x) + (-18y) = -42
(12x + 18y = 12
Both the x and y cancel each other out, and we're only left with -42 and 12, which doesn't really solve for x.
You can check the answer by checking for y. So, this time, we'll multiply the equations by (-9) and 3, which are the numbers in front of y.
(2x + 3y = 7) * (-9)
(6x + 9y = 6) * 3
___________
(-18x) + (-27y) = -63
18x + 27y = 18
Both x and y cancel out, and we're left with -63 and 18.