119k views
2 votes
Divide using long division or synthetic division:

(10x^3-x^2-29x-30)/(x^2-x-2)

User Ehmicky
by
5.3k points

1 Answer

4 votes

Answer:

10 x^3 - x^2 - 29 x - 30 = (10 x + 9)(x^2 - x - 2) + -12

Explanation:

Compute (10 x^3 - x^2 - 29 x - 30) รท (x^2 - x - 2) using polynomial long division:

x^2 - x - 2 | 10 x^3 | - | x^2 | - | 29 x | - | 30

To eliminate the leading term of the numerator, 10 x^3, multiply x^2 - x - 2 by 10 x to get 10 x^3 - 10 x^2 - 20 x. Write 10 x on top of the division bracket and subtract 10 x^3 - 10 x^2 - 20 x from 10 x^3 - x^2 - 29 x - 30 to get 9 x^2 - 9 x - 30:

| | | | | 10 x | |

x^2 - x - 2 | 10 x^3 | - | x^2 | - | 29 x | - | 30

| -(10 x^3 | - | 10 x^2 | - | 20 x) | |

| | | 9 x^2 | - | 9 x | - | 30

To eliminate the leading term of the remainder of the previous step, 9 x^2, multiply x^2 - x - 2 by 9 to get 9 x^2 - 9 x - 18. Write 9 on top of the division bracket and subtract 9 x^2 - 9 x - 18 from 9 x^2 - 9 x - 30 to get -12:

| | | | | 10 x | + | 9

x^2 - x - 2 | 10 x^3 | - | x^2 | - | 29 x | - | 30

| -(10 x^3 | - | 10 x^2 | - | 20 x) | |

| | | 9 x^2 | - | 9 x | - | 30

| | | -(9 x^2 | - | 9 x | - | 18)

| | | | | | | -12

The quotient of (10 x^3 - x^2 - 29 x - 30)/(x^2 - x - 2) is the sum of the terms on top of the division bracket. The remainder is the expression that remains after the final subtraction step.

| | | | | 10 x | + | 9 | (quotient)

x^2 - x - 2 | 10 x^3 | - | x^2 | - | 29 x | - | 30 |

| -(10 x^3 | - | 10 x^2 | - | 20 x) | | |

| | | 9 x^2 | - | 9 x | - | 30 |

| | | -(9 x^2 | - | 9 x | - | 18) |

| | | | | | | -12 | (remainder) invisible comma

(10 x^3 - x^2 - 29 x - 30)/(x^2 - x - 2) = (10 x + 9) - 12/(x^2 - x - 2)

Write the result in quotient and remainder form:

Answer: 10 x^3 - x^2 - 29 x - 30 = (10 x + 9)(x^2 - x - 2) + -12

User DGH
by
5.1k points