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A cannon ball is shot horizontally off a 86.5 m hill with an initial horizontal velocity of 105 m/s. What horizontal distance will the cannon ball travel?

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Answer:

H = 86.5 m = 1/2 g t^2 to get time for cannon ball to fall 86.5 m

t = (2 * 86.5 / 9.8)^1/2 = 4.20 sec

S = Vx t = 105 m/s * 4.2 s = 441 m horizontal distance

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