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Find the minimum value of the function f(x)=1.8x^2-6.2x+2.5 to the nearest hundredth

User PachinSV
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1 Answer

3 votes

Answer:

Below in bold.

Explanation:

f(x)=1.8x^2-6.2x+2.5

As the coefficient of x^2 is positive this has a minimum value.

Find the derivative:

f'(x) = 3.6x - 6.2

This = 0 for a minimum value of f(x):

3.6x - 6.2 = 0

x = 6.2/3.6 = 1.722

This is the value of x when f(x) is a minimum.

So, the minimum value of f(x)

= 1.8(1.722)^2 - 6.2*1.722 + 2.5

= -2.838......

= -2.84 to nearest hundredth.

User Jaydeland
by
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