33.8k views
0 votes
Jennifer states that the square root of any number is irrational. Explain why Jennifer is incorrect. PLEASE HURRY!!

1 Answer

3 votes

Answer:

See explanation below

Explanation:

A rational number is one that can be expressed as p/q where p and q are integers. An irrational number, of course, is just the opposite

Rational numbers example: 1/2, 5/6 2, 20/3, - 5/6 0, etc

Irrational numbers example: π, √2 , √3 etc

Basically the square root of a prime number is irrational
Thus √2, √7, √13 are all irrational numbers. They cannot be represented as a ratio of an integer to another integer

However, not all square roots are irrational number.

If the number is a perfect square then its square root will be a rational number

For example √36 is 6 which is a rational number (6/1)

√1 is 1 which is also a rational number

So Jennifer is incorrect in stating that the square root of any number is irrational

User Stefan Wick  MSFT
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.