Question

2. The lengths of the sides of a triangle are (2a + 1) cm, (3a + 2) cm and (4a - 1) cm. (a) Find the perimeter of the triangle in terms of a. (b) If the perimeter of the triangle is 47 cm, find the value of a. 3a + 2 4a-1 2a + 1​

Answer 1

(a) 9a + 2

(b) a = 5

Explanation:

Perimeter of a triangle = sum of sides

=

2a + 1 +
3a + 2 +
4a - 1
----------

9a + 2 Answer (a)

If perimeter = 47 , then 9a + 2 =47

Subtract 2 from both sides

==> 9a = 47 -2

9a = 45

a = 45/9

a = 5