Answer:
if you learned derivative:
f'x=(x+3)(x-2)²+(x+5)(x-2)²+2(x+5)(x+3)(x-2)
=4x³+12x²-26x-28=0
⇒x=2; =-0.84; =-4.16
⇒fx=0; =72.47; -36.97⇒fx contain (2;0); (-0.84;72.47); (-4.16;-36.97)
if x=0⇒f'x=-28<0⇒from -0.84 to 2, fx Decreasing
Explanation: