Answer:
26.565⁰
Explanation:
Triangles AEM and BEM are congruent since
AE = BE
m∠AME = m∠BME=90°
and EM is the common side
So AM = BM = AB/2 = 16/2 = 8
Triangle EAM is a right triangle with hypotenuse AE = 17 and AM = 8
So EM² = (17² - 8²) by the Pythagorean theorem
EM² = 289 - 64 = 225
EM = √225 = 15 cm
To find m∠ECM, note that triangle ECM is a right triangle with m∠EMC = 90° and the side opposite ∠EMC = EC, the side opposite ∠ECM is EM
By the law of sines
EC/sin90 = EM/sin(∠ECM)
So,
sin(∠ECM) = EM/EC since sin 90 = 1
So we have to compute EC
Again note that the triangle MCB with sides BM, MC and BC is a right triangle with m∠CBM = 90°
The hypotenuse is MC
So MC ² = MB² + BC² = 15² + 30² = 1125
MC = √1125 = 33.54 cm
Therefore
sin(∠ECM) = EM/MC = 15/33.54 = 0.4472
m∠ECM = sin⁻¹ (0.4472)
= 26.565⁰
To be honest I am not 100% sure of this answer, please check and see if this works. Thanks