Question

A piece of copper alloy with a mass of 73.0 g is

heated from 26.0◦C to 50.0◦C. In the process,
it absorbs 596 J of energy as heat. What is
the specific heat of this copper alloy?
Answer in units of J/g · K.

Answer 1

c≈0.3418 [J/(gr*K)].

Step-by-step explanation:

1) formula of heat:

Q=cm(T-t), where Q- energy of heat, c - required specifie heat, m - mass, T and t - initial and final temperatures;

2) according to the formula above:

`c=(Q)/(m(T-t));\\ c=(596)/(73*(50-26))=0.34018264840182648401826484018265[(J)/(g*K)].`

P.S. the differrence in °C is equal the difference in °K.