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3 votes
3 votes
Hii I need help ASAP with this physics question

A roller coaster has two vertical loops one after the other. The roller coaster has a speed of 7m/s at the top of the first loop with a height of 22.2m. It then proceeds around the second vertical loop with a height of 15.0m. What is the speed of the roller coaster at the top of the second vertical loop?

a.7m/s b.13.8m/s c.8.40m/s d.9.24m/s e.11.2m/s

Plz explain I can’t understand the question what I’m I supposed to use to calculate

User Erichrusch
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1 Answer

21 votes
21 votes

Between the top of the first and the top of the second loop, the coaster has lost potential energy = mgh, where h = 22.2 - 15 = 7.2m

This energy would have converted to Kinetic. Write out an equation and the masses will cancel out. Does that hint help you to find the solution? If not, I will give you another hint.

User Paul Popiel
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