Question

PLEASE HELP

What is the frequency of a photon whose energy (E) is 7.48 x 10 -6 J?​

Answer 1

1.128*10¹⁹ [GHz].

Step-by-step explanation:

1) the initial formula is

E=hν, where ν - required frequency,

2) according to the formula above

`\\u=(E)/(h);\\ \\u=(748*10^(-8))/(663*10^(-36))=1.128*10^(28)[Hz]`