Question

Select the correct answer. A mixture consists of glucose and water. What is the percent composition of glucose in the mixture if it contains 1. 3 moles of glucose (C6H12O6) and the total mass of the mixture is 276 grams? A. 17. 7% B. 26% C. 35% D. 77% E. 85%.

Answer 1

Answer: the answer is E

Explanation: plato users

Answer 2

The percent composition of glucose in the mixture is 85 % (Answer E)

Explanation:

"percent composition of glucose = (mass of glucose / mass of the mixture) x 100

Step 1: calculate the mass of glucose ( C6H12O6)

mass of glucose = moles of glucose x molar mass of glucose

molar mass of C6H12O6 = [( 12 x6) + ( 1 x12) + ( 16 x6)= 180 g/mol

mass is therefore= 1.3 moles x 180g/mol = 234 grams

Step 2: calculate the percent composition

= mass of glucose /mass of mixture x 100

= 234 g/276 g x 100 = 85 %(answer E)"