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In a given bag of M & M's, 16 were yellow, 15 were green, 21 were brown, and 11 were red.

How many M&M's were in the bag?
What fraction were yellow?
What fraction were green?
What fraction were brown?
What fraction were red?

User Tony Gibbs
by
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1 Answer

5 votes

Answer:

There are 63 M&M's in the bag when all of them are added together.

16 out of 63 (16/63) were yellow.

5 out of 21 (5/21) were green. This answer is simplified. The original is 15/63.

1 out of 3 (1/3) were brown. This answer is simplified. The original is 21/63.

11 out of 63 (11/63) were red.

Tip:

To find the fraction of something, put the total on the bottom and the wanted portion on the top.

Example: 5 yellow and 10 red birds were in a cage. Which fraction were yellow?

We put the total of birds (5+10 = 15) on the bottom and the portion wanted ("5 yellow") on the top. The fraction is 5 out of 15 (5/15). This fraction can be simplified because 5 goes into 15 three times (5 x 3 = 15), so divide the fraction 5/15 by 3 to get 1/3. (5 goes into 5 one time.)

User Felix Lange
by
8.1k points

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