Question

What is the equation of the line that passes through the point
(−3,−3) and has a slope of 3?

Answer 1

`(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-3})\hspace{10em} \stackrel{slope}{m} ~=~ 3 \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{ 3}(x-\stackrel{x_1}{(-3)}) \implies y +3= 3 (x +3) \\\\\\ y+3=3x+9\implies {\LARGE \begin{array}{llll} y=3x+6 \end{array}}`