Question

Write the slope-intercept form of the given line. Include your work in your final answer. Type your answer in the box provided to submit your solution.

Answer 1

to get the equation of any straight line, we simply need two points off of it, let's use those two from the picture below.

`(\stackrel{x_1}{-4}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3}-\stackrel{y1}{3}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-4)}}} \implies \cfrac{-6}{0 +4} \implies \cfrac{ -6 }{ 4 }\implies -\cfrac{3}{2}`

`\begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{(-4)}) \implies y -3=-\cfrac{3}{2} (x +4) \\\\\\ y-3=-\cfrac{3}{2}x-6\implies {\LARGE \begin{array}{llll} y=-\cfrac{3}{2}x-3 \end{array}}`