Question

If f(x)=ax^2+bx+c has zeros x=-11 and x=-13, what zeros does f(x-9) have?

Answer 1

If
`f(x)=0` at
`x=-11` and
`x=-13`, then we can factorize

`f(x) = ax^2 + bx + c = a (x + 11) (x + 13)`

Now,

`f(x-9) = a((x-9)+11) ((x-9)+13) = a(x+2)(x+4)`

which means the zeros of
`f(x-9)` are
`x=-2` and
`x=-4`.