Answer:
Explanation:
Given functions h(x)=x²+1 and k(x)=x-2, you want the values of (h+k)(2), (h-k)(3) and 3h(2)+2k(3).
Function evaluation
The value of a function f(x) is found by substituting the argument value for x in the function definition, then doing the arithmetic.
The value of a sum or difference of functions is the sum or difference of the values of those functions for the given argument.
(h+k)(2)
(h+k)(2) = h(2) +k(2) = (2²+1) +(2 -2) = 5 +0 = 5
(h-k)(3)
(h-k)(3) = h(3) -k(3) = (3² +1) -(3 -2) = 10 -1 = 9
3h(2) +2k(3)
3h(2) +2k(3) = 3(2² +1) +2(3 -2) = 3(5) +2(1) = 17