Question

(the cube root of 125 − 14 ÷ 2)(3 − 5)2 step by step

Answer 1

18

Explanation:

`\sf( ( ∛125 \: - \: 14 )/(2))(3 - 5)2`

Apply rule: (
`a`) =
`a`

`\sf( ( ∛125 \: - \: 14 )/(2)) = \: \sf( ∛125 \: - \: 14 )/(2)`

`= \sf (∛125 \: - \: 14 )/(2)(3 - 5)2`

Substract the numbers (3-5) = (-2)

`= \sf (∛125 \: - \: 14 )/(2)( - 2)2`

Change 2 to fraction:
`\sf (2)/(1)`

`= \sf (∛125 \: - \: 14 )/(2) * (2)/(1) ( - 2)`

Cross- cancel common factor 2

`= \sf (∛125 \: - \: 14 )/(1) ( - 2)`

Let's calculate
`\sf (∛125 \: - \: 14 )/(1)`

`= \sf (∛125 \: - \: 14 )/(1)`

Apply a fraction rule = a/1 = a

`= \sf ∛125 \: - \: 14`

`\sf = - 9`

`\sf \: = - 9( - 2)`

`\sf \: = 18`