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3 votes
A right circular cylindrical metallic rod is 16 inches tall. The radius of the base is 4 inches. What is the surface area of this metallic rod, in terms of π? the choices are 150π 140π 145π and 160π​

2 Answers

5 votes

Answer:


144\pi \: or \: 145\pi

SA to cylinder is


2\pi \: rh + \pi \: r {}^(2)

=2


2 * \pi * r \\ * h + \pi * r {}^(2)

2


2\pi * 4 * 16 + \pi * 4 * 4

answer =


144\pi \: to \: 145\pi

User Maciek
by
6.0k points
4 votes

Answer:

160π

Explanation:

The surface area of a right circular cylinder can be calculated using the following equation:


\boxed{\mathrm{Surface \ area = }2 \pi rh + 2 \pi r^2} ,

where h is the height and r is the radius of the base of the cylinder.

We are told that the rod is 16 inches tall, therefore h = 16. We are also told that the radius of the base is 4 inches, therefore r = 4. Using this information along with the formula above, we can calculate the surface area of the metallic rod:

Surface area =
(2 * \pi * 4 * 16) + (2 * \pi * (4)^2)

=
128\pi + 32\pi

=
\bf 160\pi

Therefore the surface area of the metallic rod is 160π.

User Marcel Dz
by
7.4k points
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