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Find the equation of a line parallel to y−7=−3x that passes through the point (-6,6)

User Invarbrass
by
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1 Answer

4 votes

Answer:

y = -3x - 12

Explanation:

y - 7 = -3x Put in the slope intercept form for a line

y = -3x + 7

Use the slope (-3), the x(-6) and the y(6) to find the y intercept and to write the equation for the line.

y = mx + b

6 = (-3)(-6) + b

6 = 18 + b Subtract 18 from both sides

-12 = b

y =mx + b

y = -3x -12

User Ketrox
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